How much is home insurance in Wauchula, FL?

The average cost of homeowners insurance in Wauchula varies depending on the coverage level you choose. Homeowners insurance costs $1,440 per year for dwelling coverage of $200,000 and $2,032 for $300,000 of dwelling coverage.

Below are the average annual and monthly Wauchula home insurance rates for different amounts of dwelling coverage.

Coverage level (Dwelling)Average annual rateAverage monthly rate
$200,000$1,440$120
$300,000$2,032$169
$400,000$2,671$223
$500,000$3,334$278
$600,000$3,367$281

Note: For the above rates, the deductible amount is $1,000 and liability protection is $100,000.

Cheapest homeowners insurance companies in Wauchula

Price is an important consideration when shopping for home insurance, and the cost of home insurance in Wauchula varies a lot by company. While rates matter, it’s also important to look at each company’s reputation before you buy.

According to an Insurance.com analysis, Security First Insurance is the cheapest home insurance company in Wauchula with an average annual rate of $836. The following table shows the cheapest home insurance companies in Wauchula.

Company nameAverage annual cost
Security First Insurance$836
Travelers$908
Nationwide$1,340
Universal Insurance Holding$1,830
Heritage Insurance Holdings$1,917
Progressive$2,027
FedNat Holding$2,086
Allstate$2,097
State Farm$2,255
HCI Group Inc$2,289
Citizens Property Insurance$5,831

Homeowners insurance cost in Wauchula by credit score

Homeowners with poor credit scores pay more for home insurance every year. Insurance companies in Wauchula can use credit information as one of the factors affecting the cost of your policy.

The average home insurance cost for homeowners with an excellent credit score is $1,895; that's $647 less expensive than the average cost of the same insurance for policyholders with a poor credit score. The table below shows the average annual insurance cost for homeowners with different credit levels.

Credit scoreAverage annual cost
Excellent$1,895
Fair$2,141
Good$2,032
Poor$2,542

How can you save on homeowners insurance in Wauchula?

If you're looking to save on your homeowners insurance, the best way is comparing quotes from multiple insurers. Homeowners insurance companies offer a variety of different discounts to help you lower insurance costs. There are a few different types of discounts that companies offer.

Home and auto bundle discount (multi-policy):

One of the easiest ways to get cheaper home insurance in Wauchula is the multi-policy discount, also known as bundling. If you purchase your home and auto insurance from the same company, you can save an average of $165 a year.

Loyalty discount:

Staying with the same insurance company can earn you a loyalty discount, which could save you around $2,046 annually on your home insurance in Wauchula.

Security equipment discounts:

Apart from bundling and loyalty discounts, insurance companies offer discounts to homeowners for installing safety and security equipment, like a fire alarm or burglar alarm. If you install a fire alarm at your home, you can get a discount of $83 a year on average from your insurer.

New home discount:

Besides, on If you buy new construction, you can get cheaper rates by insuring a newly constructed home, policyholders can get a new home discount of $871 a year on average. Make sure you get all the discounts for which you are eligible to trim your Wauchula homeowners insurance cost.

Methodology

Insurance.com compared homeowners insurance rates in 2022 provided by Quadrant Information Services for around 29,000 cities in all states including Washington D.C for $300,000 property damage coverage with a $1,000 deductible and $100,000 liability coverage. The rates were analyzed for almost 34,000 ZIP codes for those with good credit ratings. Content has been updated in 2023.

Compare homeowners insurance rates by city in Florida

Cape Coral
$1,507/year
Jacksonville
$1,437/year
Miami
$2,930/year
Orlando
$1,728/year
St. Petersburg
$1,112/year
Tampa
$1,625/year
Show more